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40 changes: 40 additions & 0 deletions Exercise1.sql
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-- STEP1
-- Raw table has redundancy: author name repeated across multiple posts
-- Normalization to 3NF requires separating authors from posts

-- 1NF: each cell has one value, each row is unique ✓
-- 2NF: add surrogate keys to eliminate partial dependencies
-- 3NF: separate author data into its own table (author info depends on author, not on post)
--

--Step2
--Write the DDL
CREATE TABLE authors (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(255) NOT NULL);

CREATE TABLE posts (
id INT PRIMARY KEY AUTO_INCREMENT,
author_id INT NOT NULL,
title VARCHAR(255) NOT NULL,
word_count INT,
views INT,
FOREIGN KEY (author_id) REFERENCES authors(id));



--Step3

INSERT INTO authors (name) VALUES
('Mario Wu'),
('Jospe Perez'),
('Emma Houng');

INSERT INTO posts (author_id, title, word_count, views) VALUES
(1, 'Best Paint Colors', 814, 14),
(2, 'Small Space Decorating Tips', 1146, 221),
(1, 'Hot Accessories', 986, 105),
(1, 'Mixing Textures', 765, 22),
(2, 'Kitchen Refresh', 1242, 307),
(1, 'Homemade Art Hacks', 1002, 193),
(3, 'Refinishing Wood Floors', 1571, 7542);
81 changes: 81 additions & 0 deletions Exercise2.sql
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STEP1/2

-- Raw table has three independent entities mixed together:
-- - Customer (name, status, total_mileage) → depends only on customer
-- - Aircraft (name, total_seats) → depends only on aircraft
-- - Flight (flight_number, mileage, aircraft) → depends only on flight
-- - Booking → junction between customer and flight
--

-- STEP3

-- Aircrafts table

CREATE TABLE aircrafts (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(100) NOT NULL,
total_seats INT NOT NULL);

-- Customers table

CREATE TABLE customers (
id INT PRIMARY KEY AUTO_INCREMENT,
name VARCHAR(255) NOT NULL,
status VARCHAR(50),
total_mileage INT);

-- Flights table (references aircraft)

CREATE TABLE flights (
flight_number VARCHAR(10) PRIMARY KEY,
aircraft_id INT NOT NULL,
mileage INT NOT NULL,
FOREIGN KEY (aircraft_id) REFERENCES aircrafts(id));

-- Bookings table (junction: customer ↔ flight)

CREATE TABLE bookings (
id INT PRIMARY KEY AUTO_INCREMENT,
customer_id INT NOT NULL,
flight_number VARCHAR(10) NOT NULL,
FOREIGN KEY (customer_id) REFERENCES customers(id),
FOREIGN KEY (flight_number) REFERENCES flights(flight_number));

-- STEP4

INSERT INTO aircrafts (name, total_seats) VALUES
('Boeing 747', 120),
('Airbus A330', 216),
('Boeing 777', 344);

INSERT INTO customers (name, status, total_mileage) VALUES
('Agustine Riviera', 'Silver', 1788235),
('Alaina Sepulvida', NULL, 62028),
('Tom Jones', 'Gold', 1345767),
('Sam Rio', NULL, 269653),
('Jessica James', 'Silver', 1278676),
('Ana Janco', 'Silver', 13233273),
('Jennifer Cortez', 'Gold', 3220582),
('Christian Janco', 'Silver', 1466742);

INSERT INTO flights (flight_number, aircraft_id, mileage) VALUES
('DL143', 1, 1323),
('DL122', 2, 3479),
('DL53', 3, 2988),
('DL222', 3, 10065),
('DL37', 1, 539);

INSERT INTO bookings (customer_id, flight_number) VALUES
(1, 'DL143'),
(1, 'DL121'),
(2, 'DL122'),
(3, 'DL123'),
(3, 'DL53'),
(3, 'DL242'),
(4, 'DL143'),
(4, 'DL37'),
(5, 'DL143'),
(5, 'DL142'),
(6, 'DL222'),
(7, 'DL222'),
(8, 'DL262');
49 changes: 49 additions & 0 deletions Exercise3.sql
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1. Total number of flights
SELECT COUNT(DISTINCT flight_number) AS total_flights
FROM flights;

-- 2. Average flight distance
SELECT AVG(mileage) AS avg_flight_distance
FROM flights;

-- 3. Average number of seats per aircraft
SELECT AVG(total_seats) AS avg_seats_per_aircraft
FROM aircrafts;

-- 4. Average miles flown by customers, grouped by status
SELECT status, AVG(total_mileage) AS avg_mileage
FROM customers
GROUP BY status;

-- 5. Max miles flown by customers, grouped by status
SELECT status, MAX(total_mileage) AS max_mileage
FROM customers
GROUP BY status;

-- 6. Number of aircrafts with "Boeing" in their name
SELECT COUNT(*) AS boeing_count
FROM aircrafts
WHERE name LIKE '%Boeing%';

-- 7. Flights with distance between 300 and 2000 miles
SELECT *
FROM flights
WHERE mileage BETWEEN 300 AND 2000;

-- 8. Average flight distance booked, grouped by customer status
SELECT c.status, AVG(f.mileage) AS avg_booked_distance
FROM bookings b
JOIN customers c ON b.customer_id = c.id
JOIN flights f ON b.flight_number = f.flight_number
GROUP BY c.status;

-- 9. Most booked aircraft among Gold status members
SELECT a.name, COUNT(*) AS total_bookings
FROM bookings b
JOIN customers c ON b.customer_id = c.id
JOIN flights f ON b.flight_number = f.flight_number
JOIN aircrafts a ON f.aircraft_id = a.id
WHERE c.status = 'Gold'
GROUP BY a.name
ORDER BY total_bookings DESC
LIMIT 1;