syntax error caused by unconditional __has_include usage

Encountered while working on #438.

#if __has_include(<sys/single_threaded.h>)
# include <sys/single_threaded.h>
#endif

a.cpp:1: syntax error: failed to evaluate #if condition, division/modulo by zero

It works fine when specifying -std=c++17.

I think we should default to the latest standard by default akin to Cppcheck.

I believe GCC supports __has_include for all standards, so we could also check if the standards starts with gnu....

I opened #452 which I think should give a more reasonable error message when __has_include is not defined.

I believe GCC supports __has_include for all standards, so we could also check if the standards starts with gnu....

#454 addresses this

It now reports:

a.cpp:1: syntax error: failed to evaluate #if condition, undefined function-like macro invocation: __has_include( ... )

With #454 merged it succeeds when using -std=gnu....

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