perf: avoid re-allocation if buffer is not shared - #10438
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| for i in end..len { | ||
| bit_util::unset_bit(mutable_buffer.as_slice_mut(), i); | ||
| } |
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Im sure there are faster ways to do this. I looked up a few ways to do this and im not too familar with bit operations so I left is as a basic loop for now
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Which issue does this PR close?
Buffer.into_mutableto reuse the allocation if possible intake_n_true#10251.Rationale for this change
If a boolean buffer is not shared we should re-use its allocation instead of building a new builder from scratch.
What changes are included in this PR?
match on
into_mutable, in the error case the old path is taken. If the buffer can be re-used we use it directly.Are these changes tested?
yes, existing test cover this behavior
Are there any user-facing changes?
no