fix(introduction): calculation and punctuation.

[Walentalien]

No description provided.

[drbruced12]

The punctuation change is correct.
The calculation isn't exactly wrong, given that 1KB = 1024 bytes. It's probably better to write it as (352 × 240 × 24) / (8 × 1024) = 247.5 KB.
In older editions we had some explanation about the difference between bandwidths expressed as Mbps/kbps (where the conventional assumption is M = 10^6 and k = 10^3) versus computer memory sizes in MB/KB where we assume powers of 2. I think putting the 1024 explicitly in the calculation here should remove the confusion.

[Walentalien]

The punctuation change is correct. The calculation isn't exactly wrong, given that 1KB = 1024 bytes. It's probably better to write it as (352 × 240 × 24) / (8 × 1024) = 247.5 KB. In older editions we had some explanation about the difference between bandwidths expressed as Mbps/kbps (where the conventional assumption is M = 10^6 and k = 10^3) versus computer memory sizes in MB/KB where we assume powers of 2. I think putting the 1024 explicitly in the calculation here should remove the confusion.

Made the change. Just to clarify: the book will continue to use KB/MB rather than Kib/Mib for binary units?

[llpeterson]

Accepting this PR, and then I'll add a clarifying footnote.