git.Git.execute() does not work in v3.1.11

[zm0n3]

When trying to execute any command by using the execute() method (e.g. git.Git.execute("git config --global --list") or git.Git.execute(command="git config --global --list")), this is the output I get:

*** TypeError: execute() missing 1 required positional argument: 'self'

Is this a bug?

[Byron]

I recommend reading the docs on how to use git directly to resolve this issue. The problem is trying to use an instance method as a class method.

[zm0n3]

I recommend reading the docs on how to use git directly to resolve this issue. The problem is trying to use an instance method as a class method.

Thanks Byron for pointing me the doc. So if I have to change the git global config, there's nothing I can do, am I correct?

[Byron]

You can manually instantiate a Git command like so.

[zm0n3]

You can manually instantiate a Git command like so.

I was searching a way to manage the git config --global without having a repo setup. In particular, before cloning a repo I need to ensure that the global proxy settings are correctly placed in the config list (git config --global http.proxy, otherwise all the fetch/clone commands will fail), but apparently I cannot execute any git command if I do not either have a repo set up or a repo initialized.

A workaround could be to initialize a dummy empty repo which I can use to execute the global config commands, and then delete it. But it's a dirty solution... Do you have better ideas?

Thanks in advance

[Byron]

g = Git( git_dir )
rval = g.config(…)       

git_dir can be any existing directory, it is the working directory of the git command when spawned. This doesn't need to be a repository.
Maybe try it with the invocation you need.